Quote:
Originally Posted by adhdpi
I made a miscalculation. The chance of having 2 numbers + 1 color correct is actually 9%. Because the order of the numbers is not relevant, the chance has to be increased by 6*5=30 times. 30*0.3%=9%. The chance of having 2 numbers correct (I looked this up on wikipedia) is 15.2%. So I have 1 number which had 9% chance of being correct and 2 numbers which has 15.2% chance. What are the odds of having 3 correct using 4 tickets? I don't know how to calculate this.

I happen to know a mathematician and will ask him and get back to you :)